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OpenStudy (anonymous):
A ball at rest starts rolling down a hill with a constant acceleration of 3.2 meters/second2. What is the final velocity of the ball after 6.0 seconds?
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OpenStudy (abhisar):
Here, Initial velocity (u)=0 m/s Acceleration (a) = 3.2 m/\(\sf s^2\) Time = 6 seconds We can use the equation v=u+at to find the final velocity (v)
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