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\[\sqrt{1+4\sqrt{x}}=\sqrt{x}+1\]
square both sides \[1 + 4\sqrt{x} = (\sqrt{x}+1)^2 = x + 2\sqrt{x}+1\] combine terms \[2 \sqrt{x} = x\] square both sides again \[4x = x^2\] \[x^2 -4x = x(x-4) = 0\] x = 0, x=4
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