Question

A circle has a diameter with endpoints (-8, 2) and (-2, 6).

What is the equation of the circle?

r2 = (x - 3)2 + (y + 4)2
r2 = (x - 5)2 + (y + 4)2
r2 = (x + 5)2 + (y - 4)2
r2 = (x + 3)2 + (y - 4)2

Answer 1

@madison.bush I got the answer if you need it?

Answer 2

r^2 = (x + 5)^2 + (y - 4)^2