Will give a medal and will fan if anyone can help me out and show me how it is done! Choose a word phrase for 2-p a difference of a # p & 2 b quotient of 2 and a # p c. 2 more than p d 2 decreased by a # p word phase for variable expression 1/2a+4 a 4 more than C's age b twice C's age c 4 times C's age d half C's age times 4
evaluate 8p-5 if p=6 a 8 b 43 c 48 d 81 Walker charges $30, initial fee $5 write algebraic expression for the cost of W. What is the cost of 52 walks? a 5w+30; $290 b 5w-30; $260 c 30w+5; $1,565 d 30w-5; $1,555
simplify: -|-27| a 27 b -|27| c |-27| d -27 Compare: |-10| >,<,or |5| a |-10|> |5| b |-10|< |5| c |-10|= |5| d |-10|> |5| (with a line under the <) These are it
Choose a word phrase for 2-p d 2 decreased by a # p
Thank you. Could you help with the others and maybe show me how to so them?
i wish i could say how i did it, but it was just reading comprehension don't have a method for that
evaluate 8p-5 if p=6 this i have a method for compute \[8\times 6-5\]
Alright so it would be 43?
yes
simplify: -|-27| has a method too since \(|-27|=27\) then \(-|-27|=-27\)
But what is the | ?
absolute value
oh, alright, so the answer would be -27?
yes
What about the other ones?
Compare: |-10| >,<,or |5| since \(|-10|=10\) and \(|5|=5\) we have \(|-10|>|5|\)
Alright. You just made that super easy. *Mind blown
Walker charges $30, initial fee $5 write algebraic expression for the cost of W. What is the cost of 52 walks? i have read that three times and it is missing something did you abbreviate it somehow?
yeah. A dog walker charges a $30 initial fee plus $5 per walk. Write an algebraic expression for the cost of W walks. What is the cost of 53 walks?
so for each walk he charges $5 that means \(5w\) for \(w\) walks plus the \(\$30\) for a total of \(30+5w\)
for \(52\) walks the cost would be \[30+5\times 52\]
I got 8020... Do I do the multiplication first?
Then I got 290 for multiplying first, nvm
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