Question

(1 over 4x squared Y to the -5) to the -3 (8 over x to the -5 y to the 7th) to the -1?

Answer 1

(1/4x^2y^-5)^-3 (8/x^-5y^7)^-1\[(\frac{ 1 }{ 4x ^{2} y ^{-5} } )^{-3}(\frac{ 8 }{ x ^{-5}y ^{7} })^{-1}\]