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OpenStudy (anonymous):
Null factor of: 4x^2 = 2x
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OpenStudy (anonymous):
From this we rearrange: \[0=4x^2-2x\] \[0=2x(2x-1)\] Therefore: 2x = 0, or 2x-1 = 0 Giving: x = 0, or x = 1/2 Is that what you were looking for?
OpenStudy (anonymous):
thank you
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