Question

please can any one help me??
integration of (cot2x+tan3x)dx=????

Answer 1

is it
cot2x+tan3x

or
\(cot^2 x+tan^3x\)
?

Answer 2

i think its
\( cot^ 2x+tan^3x\)

for cot^2 x , use the Pythagorean identity,
for tan^3 x, split tan^3 into tan x (tan^2 x) and then use pythagorean identity for tan^2 x

Answer 3

oh, is it just cot 2x + tan 3x ??

then you can directly use the results for integral of cot x and tan x
then just divide by the co-efficients of x

Answer 4

as we discussed in the chat,
the integral will be
(1/2) ln (sin 2x) -1/3 ln (cos 3x) +c

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