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Mathematics 21 Online
OpenStudy (anonymous):

Someone please help! Completely lost! A medication contains 9mg of active ingredients for every 1mg of inert ingredients. How much of each kind of ingredient would be contained in a single 250mg caplet??

OpenStudy (anonymous):

here, you have a 9:1 ratio of active to inert ingredients. This translates to 90% active to 10% inert. So just calculate 90% of 250 for active and 10% of 250 for inert.

OpenStudy (anonymous):

I thought you are suppose to put in an equation such as x+9x=250mg?? or am i just wrong on that?

OpenStudy (anonymous):

you can do it that way too.

OpenStudy (anonymous):

or is the equation suppose to be x=250 x 9/1= 250x 9=2250???

OpenStudy (anonymous):

No. Your first equation is correct. Set X (one of your unknowns) to be either the active or inert ingredient. Using X, you can create an expression for the other ingredient. When the 2 are added together, they should give you your total. For example, in your first equation, you set X to be inert ingredient. If you solve for X, you'll find out how much inert ingredient you have. Then using that X, you can solve the expression for the active ingredient which you made to be 9X.

OpenStudy (anonymous):

okay I came up with x=25 and the 9 x 25 =225

OpenStudy (anonymous):

nice.

OpenStudy (anonymous):

thank you so much & i have a few more questions if you wouldn't mind helping?

OpenStudy (anonymous):

sure thing.

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