Question

the numerator of a fraction is 2 less than its denominator. When both numerator and denominator are increased by 3, the fraction is increased by3/20. Find the original fraction.

Answer 1

If the denominator is x,

"the numerator of a fraction is 2 less than its denominator" =>
\[\frac{x-2}{x}\]
"When both numerator and denominator are increased by 3"=>
\[\frac{x+1}{x+3}\]
"the fraction is increased by3/20"=>
\[\frac{x-2}{x}+\frac 3{20}\]

\[\frac{x+1}{x+3}=\frac{x-2}{x}+\frac 3{20}\] Solve this