Question

how to solve (2x-5)^2+(x+7)^2=2x+3^2 using the quadratic formula

Answer 1

first get it into ax^2+bx+c=0

Answer 2

(2x-5)^2+(x+7)^2-(2x+3)^2=0
(4x^2+25)+(x^2+49)+(4x^2+9)=0
9x^2+83=0
Where would the bx come from?
@juliannescriv

Answer 3

bx would just be 0x

Answer 4

x=\[\sqrt{166i}\]