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inverse function of x-3/1+4x
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oh my a lot of algebra
you have to solve \[x=\frac{y-3}{1+4y}\] for \(y\)
you know how to do that?
no i keep getting stuck when i get to x+4xy= y-3 im not sure what to switch
\[ x+4xy= y-3 \\ x + 3 + 4xy = y \\ x + 3 = y - 4xy = y(1 - 4x) \\ \frac{x+3}{1-4x} = y \\ y = \frac{x+3}{1-4x} \]
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thanks
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