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Geometric Sequence
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@midhun.madhu1987
do you know the formula for G.P?
i am not sure @Mokeira
this is it try and substitute then tell me if you get stuck...but try first
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so \[S _{n}=20(1/4-1)/1/4-1\]
\[S _{n}=\frac{ a(r ^{n}-1) }{(r-1) }\] where r>1 Our r is 1/4 so it is less than 1, therefore we use \[S _{n}=\frac{ a(1-r ^{n}) }{( 1-r) }\] when we substitute \[\frac{ 20(1-\frac{ 1 }{ 4 }^{20}) }{1-\frac{ (1 }{4 }) }\] can you be able to simplify that
do you cross out both 1/4
no....
can you help me simplify it because this is my first time doing this.
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work out the numerator first then work out the denominator...do not think of crossing out anything..remember in the numerator only 1/4 is raised to the power 20
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