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Physics 19 Online
OpenStudy (anonymous):

A doubly charged ion is accelerated to an energy of 30.0 keV by the electric field between two parallel conducting plates separated by 1.80 cm. What is the electric field strength between the plates?

OpenStudy (aaronq):

i'm pretty sure KE=qEd

OpenStudy (anonymous):

cant get that to work

OpenStudy (anonymous):

thats right i just had to rearrange the formula

OpenStudy (anonymous):

KE=qVAB=qEd⇒ E = KE/qd=

OpenStudy (aaronq):

yep, thats it

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