Question

On a hot summer day, a young girl swings on a rope above the local swimming hole (Figure 1) . When she lets go of the rope her initial velocity is 2.10m/sm/s at an angle of 35.0 ∘^\circ above the horizontal.

Answer 1

i dont think you completed the question

Answer 2

t= 0.618s

Answer 3

i mean, what is the question asking for?

Answer 4

how high above the water was she when she go off the rope?

Answer 5

hmm can you post the figure?

Answer 6

hmm ok i guess u know this equation,
\[y=(v _{0}\sin \theta)t-1/2 g t^2\]
you need to find out "y"
@yuhan