Question

In major league baseball, the pitcher's mound is 60 feet from the batter.
If a pitcher throws a 91 mph fastball, how much time elapses from when the ball leaves the pitcher's hand until the ball reaches the batter?

Answer 1

you get it or no

Answer 2

hello

Answer 3

convert 91 mph to feet per second.

the use the formula

Time = Distance x speed

Answer 4

I got .66

Answer 5

got 5460

Answer 6

well its

\[feet/\sec = \frac{91 \times 5280}{60 \times 60}\]

when you get the feet per second



you can use Time = speed/distance

sorry about changing the equation, I just has a rethink on it...

but Time = distance/speed

will give the amount of time you have to react

Answer 7

thank you for the example

Answer 8

still don't get it

Answer 9

were did you get the other 60 from

Answer 10

ok... so the baseball travels 133.466666... feet per second

how long does it take to travel 60 ft

time = 60/133.466666...

Answer 11

hope it makes sense

Answer 12

iam good at this but it just cant get the right answer

Answer 13

well what did you get..?

Answer 14

are you happen the speed is 133.46666... feet per second..?

Answer 15

i got that

Answer 16

but were did you get the other 60

Answer 17

ok... so you are being asked how long does it take to travel 60 ft

Answer 18

so time = distance / speed

Answer 19

ok thanks if I have any more question ill ask you

Answer 20

it should be between 0.4 and 0.5 seconds... at a guess

Answer 21

it say it wrong