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Mathematics
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absolute value inequality
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where is the problem
\[2|4x+1|-5\le 1\]
okay so first add the 5 to both sides
\[2\left| 4x+1\right|=\]
6
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so then you would divide the 2 \[\left| 4x=1 \right|=\] 3
whoops add the sign into it so it makes into 2 equations
\[4x-1\le1 and -\left( 4x-1 \right)\le 1\]
then solve and you get your answer! if you need more help just ask!
you had \[|4x+1| \le 3 \] this implies you have \[-3 \le 4x+1 \le 3 \]
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then solve
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