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f(x)=2x^2+16x-7
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\[-b \pm \sqrt{b ^{2}-4ac}/2a\]
a=2,b=16 and c=-7 plug in the values
the formual is f(x)= a(x-h)^2+k
i thought uhad to find the roots..
trying to find the missing values
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f(x)=2x^2+16x-7 f(x)=2(x^2+8x)-7 f(x)=2(x^2+8x+16-16)-7 (x)=2(x^2+8x+16)-32-7 =2(x+4)^2-39 =2(x-(-4))^2-39 Source: http://www.mathskey.com/question2answer
Thank you so much
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