Question

f(x)=x^2+10x-25 find x intercept. Please help!

Answer 1

x intercepts occur when f(x) = 0

Answer 2

set the given function equal to 0 and solve x

Answer 3

f(x)= 0

x^2+10x-25 = 0

Answer 4

can you solve x ?

Answer 5

familiar with factoring a quadratic ?

Answer 6

Not really im still learning factoring a quadratic

Answer 7

there is an easy trick

Answer 8

I got (5,0)?

Answer 9

thats very close, but no

Answer 10

wait a sec , you might be correct if there is a typo in the original function

Answer 11

f(x) = x^2-10x+25

Answer 12

can you check + and - signs again ^^

Answer 13

\[-b \pm \sqrt{b ^{2}-4ac}/2a\]
a=1,b=10 and c=-25
plug in the values...can u do it from here...

Answer 14

f(x)=-x^2+10x-25 find x intercept. The x^2= -x^2

Answer 15

haha! then you're right !!

(5, 0) is the only xx intercept

Answer 16

Thank you so much

Answer 17

-x^2+10x-25 = 0

x^2 - 10x + 25 = 0

(x-5)^2 = 0

x = 5

Answer 18

so the x intercept is (5, 0)

Answer 19

And the y-intercept would be?

Answer 20

for y intercept, simply set x = 0 in the given function

Answer 21

Do I set the problem up the same way?

Answer 22

f(x) = -x^2+10x-25

f(0) = ?

Answer 23

f(x) = -x^2+10x-25

f(0) = -0^2 + 10*0 - 25
= -25

Answer 24

so the y intercept is (0, -25)

Answer 25

Im confused when it comes to adding square roots. will you always get the last number for y