Question

Find the range of the function.

f(x) = (x - 2)^2 + 2

Answer 1

since \((x-2)^2\geq 0\) for all \(x\) (since it is a square) you have
\[(x-2)^2+2\geq 2\]

Answer 2

range is \(y\geq 0\) or \([2,\infty)\)