Question

Help with Quadratic Polynomials

Answer 1

#4

\(\dfrac{10x^2y^2-35x^2y-15xy}{5xy}\)

Divide each base by 5, and subtract all the exponents by 1.

\(\dfrac{10x^2y^2}{5xy} = 2xy\)

\(\dfrac{-35x^2y}{5xy} = -7x\)

\(\dfrac{-15xy}{5xy} = -3\)

Combine them: \(2xy - 7x - 3\).

Answer 2

sorry was doing the problems rght now so i have my answer for 4 which is C but im confused on 5

Answer 3

#5, Option 1

\(\dfrac{60d^{12}e^9 + 36d^8e}{12d^4e}\)

Divide each base by 12, and subtract all the exponents on top of 'd' by 4, and subtract all the exponents on top of 'e' by 1.

\(\dfrac{60d^{12}e^9}{12d^4e} = 5d^8e^8\)

\(\dfrac{36d^8e}{12d^4e} = 3d^4\)

Combine them: \(5d^8e^8 + 3d^4\)

So Option 1 is correct.

Answer 4

so basically for #5 there would be one choice

Answer 5

which is yes

Answer 6

No, it says choose ALL that are correct. So you have to go through all of them.

Answer 7

well what i igot for my answer choices is A and C but the rest are questionable

Answer 8

#5, Option 2

\(\dfrac{42w^{20}x^9 + 7w^{12}x^{12} + 28w^4x^3}{7w^4x^3}\)

Divide each base by 7, and subtract all exponents on top of 'w' by 4, and subtract all exponents on top of 'x' by 3.

\(\dfrac{42w^{20}x^9}{7w^4x^2} = 6w^{16}x^7\)

\(\dfrac{7w^{12}x^{12}}{7w^4x^3} = w^8x^9\)

\(\dfrac{28w^4x^3}{7w^4x^3} = 4\)

Combine them: \(6w^{16}x^7 + w^8x^9 + 4\)

Option B is incorrect.

Answer 9

Option C is correct..

Answer 10

Option D is incorrect..so you are correct.

Answer 11

Option B and D both divided the exponents instead of subtracting them.

Answer 12

oh so it still woud just be one choice which is C

Answer 13

wait now im confused so
#4 is C and % is incorrect or correct

Answer 14

No it's A and C.

Answer 15

so #5 is A and C

Answer 16

like a said before

Answer 17

Yup.

Answer 18

ok thank you @iGreen now i understand
#4.C
#5.A and C

Answer 19

Yes.

Answer 20

ok thank you may you help me with one more

Answer 21

Sure