Question

1+2

Answer 1

Despite the appearance this is actually a very advanced problem. Thus, it will require several computations. Do you have a graphing calculator?

Answer 2

\[ \sum_{n = 0}^{\infty} \frac{\cosh \, p \sqrt{1 - \tanh^{2}\, p}}{2^{n}} = \, (\sin^{2} \, q \, + \, \cos^{2} \, q) + \, \ln \{ \lim_{\delta \to +\infty} \{ [(X)^{-1} - (X^{-1})] + \frac{1}{\delta} \} \}
where (X)^{-1} = (X^{-1}) .\]

Answer 3

That should get you started anyway...good luck!

Answer 4

xD nice bruh.