Question

Integral

Answer 1

\[\int\limits xsec^22xdx\] @myininaya

Answer 2

I started by setting u=x, and dv= sec^22x, so du =1 and v= tan2xdx

Answer 3

sec^2(2x) does not up to tan(2x) youve ignored the chain rule in the process

Answer 4

I just saw it :)

Answer 5

other than that, it seems fine to me :)

Answer 6

can you break down the process of obtaining "v"?