Question

e^(−2ln(10))

Answer 1

2.718281828459045−2(ln(10))
=2.718282(−2)(2.302585)
=2.718282−4.60517
=0.01

Answer 2

boxes are just negative exponent sign

Answer 3

does it help to know that
\[-2\ln(10)=\ln(10^{-2})=\ln(.01)\]?

Answer 4

and also that
\[\large e^{\ln(\spadesuit)}=\spadesuit\]