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Mathematics 6 Online
OpenStudy (anonymous):

1/(x+1)^2=1/(x+1)+2

OpenStudy (anonymous):

\[\frac{1}{(x+1)^2}=\frac{1}{(x+1)^2}+2\]?

OpenStudy (anonymous):

maybe \[\frac{1}{(x+1)^2}=\frac{1}{x+1}+2\]?

OpenStudy (x3_drummerchick):

just making sure i understand the problem correctly, its \[\frac{ 1 }{ (x+1)^{2} } = \frac{ 1 }{ (x+1)+2 }\]

OpenStudy (x3_drummerchick):

and youre solving for x? or just simplifying

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