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HELP please? If a⊗b=2a-b, determine the value of x such that 2⊗10.
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I'm going to assume this is the same as your previous question: If a ⊗ b=2a-b, determine the value of x such that 2 ⊗ x=10. (the x=10 is missing in the question) You can view the \(\otimes\) operation as doing: \(\color{red}{a} \otimes \color{blue}{b} = 2\color{red}{a} - \color{blue}{b}\) In words, think that the first element gets multiplied by 2, and then you subtract off the second element So what is \(2 \otimes x\) ? \(\begin{align}\color{red}{2}\otimes\color{blue}{x}&=2\color{red}{(2)}-\color{blue}{x}\\&=4-x \end{align}\) So now, \(~~~~~~~~~~~2 \otimes x = 10 \\ \implies 4-x = 10\) Can you solve for x now?
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