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larry mitchell invested part of his $24,000 advance at 4% annual simple interest and the rest at 3% annual simple interest. If his total yearly interest from both accounts was $760, find the amount invested at each rate
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Ok for this you are going to have to set up a system of equations
So we know that x+y=24,000 We also know that .03x+.04y=760
Solve from there by setting the first equation equal to a variable so if it was for y it is y=24,000x now plug in y to the second equation and you will figure out x
Does that make sense?
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