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Solve for i: (1+i_a)^4 = (1+i)^3
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Is the equation: \[(1+i_a)^4=(1+i)^3\]
Yeah
I tried using natural logs and got all tangled up.
Ended up with i_a+i = e
(lol)
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I am not sure what to do when a \(i_a\) occurs, but someone here should be able to.
Sorry :(
No problem, thanks anyways.
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