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How would you factor c(m - n) + d(m - n)?
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You could factor the \((m-n)\): Original Equation: \(c(m-n)+d(m-n)\) Factor the \(m-n\) \((m-n)(c+d)\)
A) cd(m - n) B) (c - d)((m - n) C) (c + d)(m - n) D) (c - d)(m + n) answers
so a?
No, c
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