Question

can some one plz help



Identify the outlier in the data. Then find the mean when the outlier is included and when it is not included
63 68 67 66 87 69 61 86 82 28

Answer 1

*means?

Answer 2

Any way,

\(1\) yd -------> \(4.47\)
\(4.50\) yd -----> \(4.47 \times 4.50 = ??\)

Answer 3

Calculate the value.. And don't forget to attach \($\) with it.. :)

Answer 4

Just do upto here, I will tell next..

Answer 5

mmmm lol this is not the question sorry hold up

Answer 6

Are you serious??

Answer 7

Identify the outlier in the data. Then find the mean when the outlier is included and when it is not included
63 68 67 66 87 69 61 86 82 28

Answer 8

mmm ya im sorry

Answer 9

Sorry, this I don't know. :)

Answer 10

@mathmath333 do you know this??

Answer 11

Or @XVasHappeninZen do you know this?

Answer 12

let me see

Answer 13

i got this no one answer it

Answer 14

so do u know the answer

Answer 15

Why have you closed the question?

Answer 16

@XVasHappeninZen don't just disclose the answer..

Answer 17

idk

Answer 18

That's my request.. :P

Answer 19

ohhh mean! nvm

Answer 20

If you don't know, then you should have opened this question till you would have known this.. :)

Answer 21

OKAY I HAVE THE ANSWERS HOLD ON

Answer 22

ok

Answer 23

mean is 67.7, outlier is 28,

and mean without outlier is 72.11111111

Answer 24

oo ok thnx

Answer 25

no problem :P

Answer 26

lol

Answer 27

Thanks for the medals <3

Answer 28

u deserved that