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Can someone PLEASE help me??? Fan&&Medal! :)) Find the non-extraneous solutions of
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|dw:1410373344372:dw| A) x = −2 B) x = −6 C) x = −6 and x = −2 D) x = 2
where the question things are, it's supposed to be negative signs..
sqrt(x+6) = x+6 => square both sides x+6 = x^2 + 36 + 12x x^2 + 11x + 30 = 0
further solve the equation to get values of x if it satisfies it isn't the extraneous solution if it doesn't than it is
That's what I got, but I'm totally confused on how the answer will be -2, 2, or -6... :(
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-6 would b ur answer @hanner_B_nanner
(x+5)(x+6) = 0 => x=-5 or x = -6 @hanner_B_nanner no other solution exists.
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