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Solve. http://lv.k12.com/mediaFiles/Ninth_Grade/Math/Unit15164/Lesson65008/05_07_LQ_4.gif A. s ≥ –2 B. s ≤ –2 C. s ≥ –18 D. s ≤ –18
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A. s greater than or equal to -2 B. s less than or equal to -2 C. s greater than or equal to -18 D. s less than or equal to -18
\[\frac{ -s }{ 3 } \ge6 \] multiply both sides by -1 to reverse inequality so it becomes \[\frac{ s }{ 3 }\le 6\] multiply both sides by 3 \[\frac{ s }{ 3 } 3 \le (-6) 3\] Can you do the rest?
Both 3's on the left side of the equation will cancel out, so all you have is -6*3. And that equals ?
Do you know?
Well since you're not replying.. (-6)+(-6)+(-6)= -18 So your answer is \[s \le -18.\]
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Hopefully you understand.
got it thx
You're welcome.
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