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Algebra 18 Online
OpenStudy (anonymous):

Express the fact that x differs from 2 by more than 3 as an inequality involving an absolute value. Solve for x.

OpenStudy (jmark):

Given statement can be written as: |x-2|>3 or -3 > x-2 > 3 Adding 2 each side, we obtain -3+2 > x-2+2 > 3 + 2 -1>x>5 x < -1 or x > 5 The value of x lies between two intervals: (-infinity, -1) or (5, +infinity) CBSE Syllabus for Class 12 Commerce : http://scoremore.beep.com/cbse-syllabus-for-class-12-commerce-2014-09-17-1.htm

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