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Please Help! Solve x3 = 125 over 27. 25 over 9 ±25 over 9 5 over 3 ±5 over 3
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what it the cubed root of 27?
The cubed root of 27 is 3x3x3, right?
it is true that \(3\times 3\times 3=27\) so the cubed root of 27 is 3 how about the cubed root of \(125\) ?
5x5x5 = 125, so the cubed root would be 5
yes
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so what is the cubed root of \(\frac{125}{27}\) ?
Would it be \[\frac{ 5 }{ 3 }\]?
yes
Thank you so much!!!
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