Question

Determine algebraically whether f(x)=1+x+x^2 is even, odd or neither

Answer 1

for even function:

f(x) = f(-x)

for odd:

-f(x) = f(-x)

Answer 2

f(x) = 1+ x + x^2
replace x by -x:

f(-x) = 1 - x + (-x)^2

which shows its not even

now work out -f(x) and see what you get