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Mathematics 10 Online
OpenStudy (anonymous):

A batch of 478 containers for frozen orange juice contains 4 that are defective. Two are selected, at random, without replacement from the batch. What is the probability that the third one selected is defective given that the first and second one selected were defective? Round your answer to three decimal places (e.g. 98.765). What is the probability that the third one selected is defective given that the first one selected was defective and the second one selected was okay? Round your answer to five decimal places (e.g. 98.76543). What is the probability that all three are defective? Round your answer to three decimal places (e.g. 98.765).

OpenStudy (adamaero):

478-2 = 476 3 defective of 476

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