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Would you help me solve 2 sq. root x + 8 = 3 sq. root x - 2? (picture in comments)
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\[2\sqrt{x + 8} = 3\sqrt{x - 2}\]
square both sides and start with \[4(x+8)=9(x-2)\] then solve a usual
@satellite73 Thank you so much I knew I needed to get rid of the radicals but wasn't sure whether to square them or not! Thanks!
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