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Mathematics 6 Online
OpenStudy (loser66):

Please, help

OpenStudy (loser66):

OpenStudy (loser66):

Please help me make it clearer.

OpenStudy (nincompoop):

yeah the logic is weak

OpenStudy (loser66):

but how to make it stronger? One more thing, the first part for one to one, I still have the case x1>0, x2 <0, but it is easy to prove f(x1) \(\neq\) f(x2)

OpenStudy (loser66):

It is one to one.

OpenStudy (loser66):

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