Question

Help on getting started please?
x^6+7x^3-8=0

Answer 1

Ah, you again :)

Your equation is

x^6 + 7x^3 - 8 = 0

right..

Let's do a substitution. Let's say that

x^3 = y

Therefore, you have

y^2 + 7y - 8 =0

Now solve this algebraically, break up the terms.

Answer 2

x to the 3rd power = -8

x^6+7x^3-8=0

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Equation:


Solution for x^6+7x^3-8=0 equation:

Simplifying
x6 + 7x3 + -8 = 0

Reorder the terms:
-8 + 7x3 + x6 = 0

Solving
-8 + 7x3 + x6 = 0

Solving for variable 'x'.

Factor a trinomial.
(-8 + -1x3)(1 + -1x3) = 0

Answer 3

Never mind, ^^^ the person above me will tell you how

Answer 4

Breaking up the term, you would get

\[y^{2}+8y-y-8\]
\[y(y+8)-1(y+8)\]
\[(y-1)(y+8)\]
Hence
\[y=1\]
or
\[y=-8\]

Now, remember that
\[x^{3} = y\]
so
\[x^{3} = -8\]
or
\[x^{3} = 1\]

Solve both of the equations and you have

\[x=-2\] or
\[x=1\]

I hope my answer helped you. If it solves your qeustion be sure to mark it as Best Response and close the question. Glad to be of help. -swas

Answer 5

LOL @Jennaluv Equation solver?

Answer 6

Yes, thought i would try something new....... cx

Answer 7

But how did you know?

Answer 8

@Jennaluv : You forgot to edit your answer :)

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