a wire of length 200cm is cut into 2 parts and each part is bent to form a square. if the area of the larger square is 9 times that of the smaller square, find the perimeter of the larger square. (use quadratic formula if possible)

Question

shinalcantara · Answer

will you please recheck the statement "if the sum of the area..." that line

zpupster · Answer

area of first square= x^2
area 2nd square = (200-x)^2

first square 9 time bigger so.......

9x^2 = (200-x)^2
9x^2=40000-400x+x^2  add - 9x^2 to both sides
0 = -8x^2 - 400 x + 40000  factor out -8 and divide both sides by -8

then you could use the quadratic formula or just factor

shinalcantara · Answer

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