Question

If 3 cows can eat 16 bales of hay in 8 days, how long will it take 9 cows to eat 7 bales of hay?

Answer 1

16/8 = 2/1
3 cows eat at a rate of 2 bales per day

multiply by 3
9 cows then eat at rate of 6 bales per day

set up proportion using daily rate
\[\frac{7}{d} = \frac{6}{1}\]
\[d = \frac{7}{6}\]
It take 9 cows (7/6) days to eat 7 bales of hay