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Mathematics 14 Online
OpenStudy (anonymous):

lx+6l=2x solve and check for extraneous solutions When i solved this i got x=6 but I'm not sure what to do to check for extraneous solutions.

OpenStudy (anonymous):

Hello again. Have you figured it out or do you still need help?

OpenStudy (anonymous):

Hello, I still would like some help.

OpenStudy (anonymous):

@Zenitho

OpenStudy (anonymous):

Sorry, I didn't see the reply for some reason.

OpenStudy (anonymous):

So, if you set it up like this, lx+6l=2x x + 6 = 2x x + 6 = -2x Then solve for x in both cases. You'll get the two answers =0)

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