Question

(sinA+cosecA)^2+(cosA+secA)^2=(1+secAcoseA)^2

Answer 1

open the square

Answer 2

sin^2+cosec ^2 +2sin*cosec+cos^2+sec^2+2cos*sec
sinA*cosecA=1
cosA*secA=1
sin^2A+cos^2A=1
1+cosec^2+2+sec^2+2

Answer 3

now solve it further

Answer 4

here 4 will come... how we can remove it

Answer 5

This is not an identity: http://www.wolframalpha.com/input/?i=%28sinx%2Bcscx%29%5E2%2B%28cosx%2Bsecx%29%5E2%3D%281%2Bsecx*cscx%29%5E2

I suspect you have an error in the original question, or are you supposed to find a solution?