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OpenStudy (anonymous):
(b+2)/(2b2−b−1) − (1)/(b−1)= A. −12b+1 B. −b+1(2b+1)(b−1) C. b+1(2b+1)(b−1) D. b+12b2
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OpenStudy (anonymous):
|dw:1410718258056:dw|
OpenStudy (midhun.madhu1987):
|dw:1410719253091:dw|
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