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Two forces act on the screw eye. If F1=440N and F2=600N, determine the angle theta(0
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dot product of two vector forces\[\vec{F_1}\bullet\vec{F_2}=|\vec{F_1}||\vec{F_2}|\cos\theta\]we can use Cosine Law... to find the angle theta opposite to resultant force of 760N... forces F1 and F2 the other two legs of the triangle...
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