A census found that 52.2% of adults are female, 10.2% are divorced, and 5.9% are divorced females. For an adult selected at random let F be the even that the person if female and d is divorced. Find the probability that the person selected at random is A) female P(F)=52.5/100=.522 (B)divorced P(D)=102/100=.102 (C) a divorced female P(DF)5.9/100=.059 (D) female or divorced P(FUD)???(E) male P(M)=100-52.2=47.8/100=.478 (F) neither female or divorce (unsure of this one as well??). Could someone please see that I am doing this correct as well as what I have gotten stuck on?

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