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OpenStudy (anonymous):
Need help on geting started please... 2x^2/3-5x^1/3-3=0
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jimthompson5910 (jim_thompson5910):
let z = x^(1/3) square both sides to get z^2 = [ x^(1/3) ]^2 z^2 = x^(2/3)
jimthompson5910 (jim_thompson5910):
so the original equation turns into 2z^2 - 5z - 3 = 0 use the quadratic formula to solve for z to get z = ??? or z = ???
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