Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

(AB' + CD) (B'E + CD)

OpenStudy (anonymous):

LET CD = Z (AB' + Z)(B'E + Z) AB'B'E + AB'Z + B'EZ + ZZ AB'B'E + AB'Z + B'EZ + Z AB'E + AB'Z + B'EZ + Z AB'E + Z ( AB' + B'E + 1) AB'E + Z(0) = AB'E+ Z

OpenStudy (rational):

FOIL ?

OpenStudy (anonymous):

anyone can confirm?

OpenStudy (anonymous):

i'm just not sure about AB'B'E = AB'E since B'*B' is B'

OpenStudy (rational):

(AB' + CD) (B'E + CD) AB'E + B'CDE + AB'CD + CD AB'E + CD(B'E + AB' + 1) AB'E + CD(1) AB'E + CD

OpenStudy (anonymous):

yeah mixed the basic theorems up

OpenStudy (rational):

x+1 = 1

OpenStudy (rational):

x*1 = x

OpenStudy (rational):

x*x = x x+x = x

OpenStudy (anonymous):

got any simple ways to remember this

OpenStudy (anonymous):

x and true = x?

OpenStudy (rational):

yes

OpenStudy (anonymous):

yes that's true but how would you think of it in english to grasp the concept

OpenStudy (rational):

whats the definition of AND ?

OpenStudy (rational):

both the statements must be true for AND to evaluate to true, right ?

OpenStudy (anonymous):

|dw:1410756825525:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!