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OpenStudy (anonymous):
help? 1/2< or equal to x+1/3 < 3/4
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OpenStudy (shadowlegendx.):
\[\frac{ 1 }{ 2 } \le x+ \frac{ 1 }{ 3 } < \frac{ 3 }{ 4 }\]
OpenStudy (shadowlegendx.):
You need to find the LCD, Least Common Denominator to solve this
OpenStudy (shadowlegendx.):
Once you do, convert the fractions and solve
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