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Find the average rate of change for the function over the given interval g(x)=e^x (0,1)
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Average rate for a function \(g(x))\) over an interval \((a, b)\) is" \[\frac{g(b)-g(a)}{b-a} \]
i got that but does the e mean anything? or would it just be e^1?
\(e^1=e\) :)
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