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Solve for x: |x − 2| + 10 = 12 x = 0 and x = 4 x = −4 and x = 0 x = −20 and x = 4 No solution
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why
|x-2|=12-10=2
You have to solve two equations: x - 2 + 10 = 12 and x + 2 + 10 = 12 ---------------------- x - 2 + 10 = 12 Add: x + 8 = 12 Subtract 8 to both sides: x = 4 ----------------------------- x + 2 + 10 = 12 Add: x + 12 = 12 Subtract 12 to both sides: x = 0
now mode will alwys give positive value
So your answer is x = 4, x = 0(Option A).
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so to remove mode to condition will be there \[x-2=\pm 2\]
x-2=2 -----> x=2+2=4--->X=4 x-2=-2----->X=-2+2---->X=0
what is the anwer
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