Solve for x: |x − 2| + 10 = 12

x = 0 and x = 4

x = −4 and x = 0

x = −20 and x = 4

No solution

Question

Solve for x: |x − 2| + 10 = 12

 x = 0 and x = 4

 x = −4 and x = 0

 x = −20 and x = 4

 No solution

anonymous · Answer

why

gorv · Answer

|x-2|=12-10=2

igreen · Answer

You have to solve two equations:

x - 2 + 10 = 12

and

x + 2 + 10 = 12

----------------------

x - 2 + 10 = 12

Add:

x + 8 = 12

Subtract 8 to both sides:

x = 4

-----------------------------

x + 2 + 10 = 12

Add:

x + 12 = 12

Subtract 12 to both sides:

x = 0

gorv · Answer

now mode will alwys give positive value

igreen · Answer

So your answer is x = 4, x = 0(Option A).

gorv · Answer

so to remove mode to condition will be there
$$x-2=\pm 2$$

gorv · Answer

x-2=2  -----> x=2+2=4--->X=4
x-2=-2----->X=-2+2---->X=0

anonymous · Answer

what is the anwer